Evaluation of Integrals

*wherever the variables a or b are mentioned, they refer to the integral existance theorem, where 'If f is continuous on [a,b], then f is integrable on [a,b]'.

*dark blue text represents the equation, dark red represents notes in the midst.

Another issue - this one halfway through Chapter 5 (The Integral).

∫ (where b=1 and a=0) (3x^2 + 2√x + 3[cube root]x) dx

Okay, so it looks pretty simple. I mean, it's only one line. But I quickly managed to get tangled up and lost. I tried using the antiderivative form of the generalized power rule, but that left me a royal mess.

... the answer key informs me that the answer is 55/12.

Ideas? Help? *looks pointedly at Snoink and Incan who havn't been in TNS...* ^_~

Dream Deep--


Break your integral up. For instance, that first term after integration pretty obviously becomes x^3, which evaluated from 1 to 0 is going to be (1)^3-(0)^3=1. The other two simply require you to change your roots into exponents and solve from there.


Best,
Brad

Ah, thanks Brad. Ill do that. It should work this time - if not I'll give you a holler. ^_~

Much appreciate it.